In a class test in mathematics and English, it was found that 55 students have passed in Mathematics, 46 have passed in English and 35 passed in both the subjects. If the number of students who appeared in the test is 100, the find (i) the percentage of unsuccessful students in both subjects. (ii) the percentage of students who have passed in Mathematics only. (iii) the percentage of students who have passed in English only.
Solution:
Let, set of students who have passed in Mathematics be M
Set of students who have passed in English be E
Given,
n(M)= 55,
n(E)= 46,
n(MꓵE)= 35
We know that,
n(MUE)= n(M) + n(E) – n(MꓵE)
= 55 + 46 – 35
= 66
(i) Number of students unsuccessful both subjects
= n(MꓵE)ˊ
= n(U) - n(MUE)
= 100 – 66
= 34
Therefore, the percentage of unsuccessful students in both subjects
= 34%
(ii) Number of students who have passed in Mathematics
= n(M – E)
= n(M) - n(MꓵE)
= 55 – 35
= 20
Therefore, the percentage of students who have passed in Mathematics= 20%
(iii) Number of students who have passed in English
= n(E – M)
= n(E) - n(MꓵE)
= 46 – 35
= 11
Therefore, the percentage of students who have passed in English= 11%
Exercise: 1.1