In a survey among 1500 families of a town it was found that 1263 families have TV, 639 families have radio and 197 families have neither TV nor Radio. (i) how many families in that town have both radio and TV? (ii) how many families have TV only, but no radio? ( iii) how many families have radio only, but no TV.
Let total set of families be U
The set of families have TV be T
The set of families have radio be R
Given,
n(T)= 1263,
n(R)=639
n(TˊꓵRˊ)= 197
Now,
n(TˊꓵRˊ)= n(U) – n(TUR)
⇒ 197 = 1500 - n(TUR)
⇒ n(TUR)= 1500 – 197
⇒ n(TUR)= 1303
(i) the number of families in that town have both radio and TV,
n(TꓵR) = n(T) + n(R) – n(TUR)
= 1263 + 639 – 1303
= 599
(ii) the number of families have TV only, but no radio,
n(T – R)= n(T) - n(TꓵR)
= 1263 – 599
= 664
(iii) the number of families have radio only, but no TV,
n(R – T)= n(R) - n(TꓵR)
= 639 – 599
= 40
Exercise: 1.1