3. If n(AꓵB)= 36, n(A – B)= 25, n(B – A)= 20, Then find n(AUB), n(A) and n(B) - Advance Math Class 10 - Exercise: 1.1

If  n(A – B)= 25, n(B – A)= 20, Then find n(AUB), n(A) and  n(B).

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Solution:

We know that,

n(AUB)= n(A – B) + n(B – A) + n(AꓵB)

= 25 + 20 + 36

= 81

n(A)= n(A – B) + n(AꓵB)

= 25 + 36

= 61

n(B)= n(B – A) + n(AꓵB)

= 20 + 36

= 56

  Exercise: 1.1  

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