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9. In a class of 90 students, 60 students play volleyball, 53 students play badminton and 35 students play both of the games. Find the number of students (i) who do not play any one of the two games (ii) who play badminton only, but not volleyball (iii) who play volleyball only, but not badminton (iv)who play at least one of two games? Advance Math Class 10 - Exercise: 1.1

In a class of 90 students, 60 students play volleyball, 53 students play badminton and 35 students play both of the games. Find the number of students (i) who do not play any one of the two games (ii) who play badminton only, but not volleyball (iii) who play volleyball only, but not badminton (iv)who play at least one of two games?

Let the set students play volleyball be V and

The set of students play badminton be B and set of universal be U

Given, 
n(U)= 90
n(V)= 60
n(B)= 53
n(VꓵB)= 35

Therefore,
9. In a class of 90 students, 60 students play volleyball, 53 students play badminton and 35 students play both of the games. Find the number of students (i)  who do not play any one of the two games (ii) who play badminton only, but not volleyball  (iii) who play volleyball only, but not badminton  (iv)who play at least one of two games? Advance Math Class 10 - Exercise: 1.1
             = 60 + 53 – 35
             = 78

(i) number of students who do not play any one of the two games,
=n(U)-n(VUB)
= 90 – 78
= 12

(ii) the number of students who play badminton only, but not volleyball,
n(B – V)= n(B) - n(VꓵB)
              = 53 – 35
              = 18

(iii) the number of students who play volleyball only, but not badminton,
n(V – B)= n(V) - n(VꓵB)
              = 60 – 35
              = 25

(iv) the number of students who play at least one of two games,
n(VUB)= n(V) + n(B) - n(VꓵB)
             = 60 + 53 – 35
             = 78


  Exercise: 1.1  










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