Show that \left ( a+b \right )\left ( \frac{1}{a}+ \frac{1}{b} \right )>4

Solution:

⇨We have to show

$Show that \left ( a+b \right )\left ( \frac{1}{a}+ \frac{1}{b} \right )>4$

⇨Adding 2ab On both side

$Show that \left ( a+b \right )\left ( \frac{1}{a}+ \frac{1}{b} \right )>4$
$Show that \left ( a+b \right )\left ( \frac{1}{a}+ \frac{1}{b} \right )>4$
$Show that \left ( a+b \right )\left ( \frac{1}{a}+ \frac{1}{b} \right )>4$
$Show that \left ( a+b \right )\left ( \frac{1}{a}+ \frac{1}{b} \right )>4$
$Show that \left ( a+b \right )\left ( \frac{1}{a}+ \frac{1}{b} \right )>4$
$Show that \left ( a+b \right )\left ( \frac{1}{a}+ \frac{1}{b} \right )>4$
$Show that \left ( a+b \right )\left ( \frac{1}{a}+ \frac{1}{b} \right )>4$ Proved