If a > 0, b > 0, a > b then \frac{1}{a}<\frac{1}{b}

Solution:

⇨ We have e to show

$If a > 0, b > 0, a > b then \frac{1}{a}<\frac{1}{b}$

⇨Given that
⇨ $If a > 0, b > 0, a > b then \frac{1}{a}<\frac{1}{b}$
⇨ $b>0 ......(ii)$
$If a > 0, b > 0, a > b then \frac{1}{a}<\frac{1}{b}$
$If a > 0, b > 0, a > b then \frac{1}{a}<\frac{1}{b}$
⇨Again $If a > 0, b > 0, a > b then \frac{1}{a}<\frac{1}{b}$
$If a > 0, b > 0, a > b then \frac{1}{a}<\frac{1}{b}$
$If a > 0, b > 0, a > b then \frac{1}{a}<\frac{1}{b}$
$If a > 0, b > 0, a > b then \frac{1}{a}<\frac{1}{b}$ Proved

If a > 0, b > 0, a > b then \frac{1}{a}<\frac{1}{b}

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