The Biotic World is the best free Educational Website for Students. The Biotic World Provides NCERT Solution PDF, CBSE Notes PDF, NCERT Books PDF for class 8, 9, 10, 11, 12. The Biotic World also provides GU TDC Syllabus, Previous Years Question Papers, TDC notes on different topics of Physics, Chemistry, Mathematics, Zoology and Botany any many more.
So, Follow us to get tuned with latest updates.
Solution:
⇒ Given
r = 28 cm
Cost of making design = 0.35 per ![\large cm^{2}](https://latex.codecogs.com/gif.latex?\dpi{120}&space;\large&space;cm^{2})
⇒ Here we can see, there are 6 isosceles △ with equal area
⇒ Angle (𝚹) of sector in one △
⇒ Area of sector OAPB
⇒ Area of such 6 sector
= 6 x 410.67
= 2464.02 ![\large cm^{2}](https://latex.codecogs.com/gif.latex?\dpi{120}&space;\large&space;cm^{2})
⇒ From △ AOB
⇒ In △ AMO
𝚹 = 60/2 = 30°
AO = r = 28 cm
∴ cos 30° = b/h = MO/AO
⇒ √ 3/2 = MO/28
⇒ √ 3 x 28/2 = MO
⇒ MO = 1.7 x 14
⇒ MO = 23.8 cm
⇒ Again
sin 30° = p/h = AM/AO
⇒ 1/2 = AM/28
⇒ AM = 28/2
⇒ AM = 14 cm
⇒ AB = AM + MB
⇒ AB = AM + AM (∴ AM=MB)
⇒ AB = 2AM
⇒ Area of △ AOB
⇒ Area of 6 such △
= 6 x 333.2
= 1999.2 ![\large cm^{2}](https://latex.codecogs.com/gif.latex?\dpi{120}&space;\large&space;cm^{2})
⇒ Area of design
= Area of 6 sector - Area of 6 △
= (2464.02 - 1999.2) ![\large cm^{2}](https://latex.codecogs.com/gif.latex?\dpi{120}&space;\large&space;cm^{2})
= 464.82 ![\large cm^{2}](https://latex.codecogs.com/gif.latex?\dpi{120}&space;\large&space;cm^{2})
⇒ The cost of making the design
= 464.82 x 0.35
= 162.687 Rs
Exercise 12.2