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Solution:
⇒ Given
r = 28 cm
Cost of making design = 0.35 per
⇒ Here we can see, there are 6 isosceles △ with equal area
⇒ Angle (𝚹) of sector in one △
⇒ Area of sector OAPB
⇒ Area of such 6 sector
= 6 x 410.67
= 2464.02
⇒ From △ AOB
⇒ In △ AMO
𝚹 = 60/2 = 30°
AO = r = 28 cm
∴ cos 30° = b/h = MO/AO
⇒ √ 3/2 = MO/28
⇒ √ 3 x 28/2 = MO
⇒ MO = 1.7 x 14
⇒ MO = 23.8 cm
⇒ Again
sin 30° = p/h = AM/AO
⇒ 1/2 = AM/28
⇒ AM = 28/2
⇒ AM = 14 cm
⇒ AB = AM + MB
⇒ AB = AM + AM (∴ AM=MB)
⇒ AB = 2AM
⇒ Area of △ AOB
⇒ Area of 6 such △
= 6 x 333.2
= 1999.2
⇒ Area of design
= Area of 6 sector - Area of 6 △
= (2464.02 - 1999.2)
= 464.82
⇒ The cost of making the design
= 464.82 x 0.35
= 162.687 Rs
Exercise 12.2