A round table cover has six equal designs as shown in Fig. 12.14. If the radius of the cover is 28 cm, find the cost of making the designs at the rate of ` 0.35 per cm2 ? (Use √ 3 = 1.7)
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Solution:
⇒ Given
r = 28 cm
Cost of making design = 0.35 per 
⇒ Here we can see, there are 6 isosceles △ with equal area
⇒ Angle (𝚹) of sector in one △
⇒ Area of sector OAPB
⇒ Area of such 6 sector
= 6 x 410.67
= 2464.02 
⇒ From △ AOB
⇒ In △ AMO
𝚹 = 60/2 = 30°
AO = r = 28 cm
∴ cos 30° = b/h = MO/AO
⇒ √ 3/2 = MO/28
⇒ √ 3 x 28/2 = MO
⇒ MO = 1.7 x 14
⇒ MO = 23.8 cm
⇒ Again
sin 30° = p/h = AM/AO
⇒ 1/2 = AM/28
⇒ AM = 28/2
⇒ AM = 14 cm
⇒ AB = AM + MB
⇒ AB = AM + AM (∴ AM=MB)
⇒ AB = 2AM
⇒ Area of △ AOB
⇒ Area of 6 such △
= 6 x 333.2
= 1999.2 
⇒ Area of design
= Area of 6 sector - Area of 6 △
= (2464.02 - 1999.2) 
= 464.82 
⇒ The cost of making the design
= 464.82 x 0.35
= 162.687 Rs
Exercise 12.2