A chord of a circle of radius 15 cm subtends an angle of 60° at the center. Find the areas of the corresponding minor and major segments of the circle ? (Use π = 3.14 and √ 3 = 1.73)

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Solution:
⇨ Given
    r = 15 cm
∴ OB = OA = 15 cm
    θ = 60°
⇨ Area Of Circle
⇨ Area Of Circle

⇨ Area Of Minor Sector
⇨ Area Of Minor Sector



⇨ Area Of Equilateral △ AOB
⇨ Area Of Equilateral △ AOB

⇨ Area Of Minor segment
Area Of Minor Sector - Area Of Equilateral △ AOB
= 117.75 - 97.3125
= 20.4375 

⇨ Area Of Major segment
=  Area Of Circle - Area Of Minor segment
= 706.5 - 20.4375
= 686.0625 


  Exercise 12.2  
















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