Find the smallest integers with which 5324 to be multiplied so that it becomes a perfect cube ?

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Find the smallest integers with which 5324 to be multiplied so that it becomes a perfect cube ?


Solution:
⇨ Expanding 5324 as the factors of prime numbers.
⇨ 5324 = 2 x 2 x 11 x 11 x 11
⇨ Here 2 do not have complete triplet it requires one more 2 to become triplet. So for a perfect cube it must be multiplied by at least 2 to complete the triplet.

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