The amount of money in the account every year, when ₹ 10000 is deposited at compound interest at 8 % per annum.

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Solution:

⇒Amount deposited, P = ₹ 10000

⇒Interest rate , R = 8 % pa

⇒T = Time

⇒Compound Interest for T = 1 Year

⇒We know, Compound Interest

$https://latex.codecogs.com/gif.image?\large \dpi{120}=P\left\{1+\frac{R}{100} \right\}^{T}$

$https://latex.codecogs.com/gif.image?\large \dpi{120}=10000\left\{1+\frac{8}{100} \right\}^{1}$

$https://latex.codecogs.com/gif.image?\large \dpi{120}=10000\left\{\frac{100+8}{100} \right\}^{1}$

$https://latex.codecogs.com/gif.image?\large \dpi{120}=10000\left\{\frac{108}{100} \right\}$

$https://latex.codecogs.com/gif.image?\large \dpi{120}=10000\times \frac{108}{100}$

$https://latex.codecogs.com/gif.image?\large \dpi{120}=100\times 108$

$https://latex.codecogs.com/gif.image?\large \dpi{120}=10800$

⇒Compound Interest for T = 2 Years

$https://latex.codecogs.com/gif.image?\large \dpi{120}=10000\left\{\frac{108}{100} \right\}^{2}$

$https://latex.codecogs.com/gif.image?\large \dpi{120}=11664$

⇒Compound Interest for T = 3 Years

$https://latex.codecogs.com/gif.image?\large \dpi{120}=10000\left\{\frac{108}{100} \right\}^{3}$

$https://latex.codecogs.com/gif.image?\large \dpi{120}=12597.12$

⇒As $Ex-5.1 (1) (iv) The amount of money in the account every year, when ₹ 10000 is deposited at compound interest at 8 % per annum.$ i.e. difference is not same so its not in AP.

Ex-5.1 (1) (iv) The amount of money in the account every year, when ₹ 10000 is deposited at compound interest at 8 % per annum.

The amount of money in the account every year, when ₹ 10000 is deposited at compound interest at 8 % per annum.

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