Find the area of the shaded region in Fig. 12.22, where a circular arc of radius 6 cm has been drawn with vertex O of an equilateral triangle OAB of side 12 cm as center ?

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Find the area of the shaded region in Fig. 12.22, where a circular arc of radius 6 cm has been drawn with vertex O of an equilateral triangle OAB of side 12 cm as center ?<img src="https://latex.codecogs.com/gif.latex?\dpi{120}&space;\large&space;=&space;\frac{300}{360}\times&space;\frac{22}{7}\times&space;6^{2}&plus;\frac{\sqrt{3}\times&space;12^{2}}{4}" title="\large = \frac{300}{360}\times \frac{22}{7}\times 6^{2}+\frac{\sqrt{3}\times 12^{2}}{4}" />
⇒ Given
    r = 6 cm
    Sides of △ = 12 cm
    Angles in Equilateral triangle, 𝛉1 = 60°
    ∴ Angle of major sector in circle, 𝛉2 = 360 - 60 = 300°
⇒ Area of shaded region
= Area of major sector of circle + Area of Equilateral triangle
= Area of major sector of circle + Area of Equilateral triangle
= Area of major sector of circle + Area of Equilateral triangle
= Area of major sector of circle + Area of Equilateral triangle
= Area of major sector of circle + Area of Equilateral triangle
= Area of major sector of circle + Area of Equilateral triangle



  Exercise:12.3  
















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