Find two consecutive positive integers, sum of whose squares is 365 ?

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Solution:
⇨ Let the two consecutive positive integers are x, x+1
A/Q

    Find two consecutive positive integers, sum of whose squares is 365.

⇨Divided by 2 on both side

⇨x = -14, We only consider positive integers, so -14 is rejected.
⇨Therefore, Two consecutive positive integers are = x , x+1 
13 , 13+1
⇨13, 14


  Exercise 4.2  

1. Find the roots of the following quadratic equations by factorisation: 









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