Find the compound interest : p= Rs 10000, r= 12 % , n= 2 ?

byAmlesh Mahato •March 10, 2021

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Solution:

⇨Given

⇨p = Rs 10000

⇨r = 12 %

⇨n = 2

⇨Compound interest will be

$Find the compound interest : p= Rs 10000, r= 12 % , n= 2 .$

$\large \Rightarrow C.I=p\left ( 1+\frac{r}{100} \right )^{n}-p$

$\large \Rightarrow C.I=p\left \{ \left ( 1+\frac{r}{100} \right )^{n}-1 \right \}$

$\large \Rightarrow C.I=10000\left \{ \left ( \frac{100+12}{100} \right )^{2}-1 \right \}$ $\large \Rightarrow C.I=10000\left \{ \left ( \frac{112}{100} \right )^{2}-1 \right \}$

$\large \Rightarrow C.I=10000\left \{ \frac{12544}{10000}-1 \right \}$

$\large \Rightarrow C.I=10000\left \{ \frac{12544-10000}{10000} \right \}$

$\large \Rightarrow C.I=10000\times \frac{2544}{10000}$

$\large \Rightarrow C.I=2544$ Rs

Tags: Math-Class-8

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