Umesh set up a small factory by investing ₹40,000. During the first three successive years his profits were 5%,10% and 15% respectively. If each year the profit was on previous years' capital, calculate his total profit.

byAmlesh Mahato •October 09, 2020

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Solution:

⇨Given

⇨p=40000

⇨r1=5%

⇨r2=10%

⇨r3=15%

⇨Simple interest for 1st year will be

$\large S.I=\frac{p\times r_{1} \times n}{100}$

$\large \Rightarrow S.I=\frac{40000\times 5\times 1}{100}$

$\large \Rightarrow S.I=2000$ Rs

⇨Total money invested in 2nd year=40000 + 2000 = 42000 Rs

⇨A/Q

⇨Profit in 2nd year =10%

⇨Then Simple interest for 2nd year will be

$\large S.I=\frac{p\times r_{2}\times n}{100}$

$\large \Rightarrow S.I=\frac{42000\times 10\times 1}{100}$

$\large \Rightarrow S.I=420\times 10\times 1$

$\large \Rightarrow S.I=4200$ Rs

⇨Total money invested in 3rd year

= 42000 + 4200

= 46200 Rs

⇨Profit in 2nd year =15%

⇨Then Simple interest for 3rd year will be

$\large S.I=\frac{p\times r_{3}\times n}{100}$

$\large \Rightarrow S.I=\frac{46200\times 15\times 1}{100}$

$\large \Rightarrow S.I=462\times 15\times 1$

$\large \Rightarrow S.I=6930$ Rs

⇨Total Money After 3 years

= 46200 + 6930

= 53130 Rs

⇨Therefore total profit will be

= 53130 - 40000

= 13130 Rs

Tags: Math-Class-8

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