Umesh set up a small factory by investing ₹40,000. During the first three successive years his profits were 5%,10% and 15% respectively. If each year the profit was on previous years' capital, calculate his total profit.

byAmlesh Mahato •October 09, 2020

The Biotic World is the best free Educational Website for Students. The Biotic World Provides NCERT Solution PDF, CBSE Notes PDF, NCERT Books PDF for class 8, 9, 10, 11, 12. The Biotic World also provides GU TDC Syllabus, Previous Years Question Papers, TDC notes on different topics of Physics, Chemistry, Mathematics, Zoology and Botany any many more. So, Follow us to get tuned with latest updates.

Solution:

⇨Given

⇨p=40000

⇨r1=5%

⇨r2=10%

⇨r3=15%

⇨Simple interest for 1st year will be

$\large S.I=\frac{p\times r_{1} \times n}{100}$

$\large \Rightarrow S.I=\frac{40000\times 5\times 1}{100}$

$\large \Rightarrow S.I=2000$ Rs

⇨Total money invested in 2nd year=40000 + 2000 = 42000 Rs

⇨A/Q

⇨Profit in 2nd year =10%

⇨Then Simple interest for 2nd year will be

$\large S.I=\frac{p\times r_{2}\times n}{100}$

$\large \Rightarrow S.I=\frac{42000\times 10\times 1}{100}$

$\large \Rightarrow S.I=420\times 10\times 1$

$\large \Rightarrow S.I=4200$ Rs

⇨Total money invested in 3rd year

= 42000 + 4200

= 46200 Rs

⇨Profit in 2nd year =15%

⇨Then Simple interest for 3rd year will be

$\large S.I=\frac{p\times r_{3}\times n}{100}$

$\large \Rightarrow S.I=\frac{46200\times 15\times 1}{100}$

$\large \Rightarrow S.I=462\times 15\times 1$

$\large \Rightarrow S.I=6930$ Rs

⇨Total Money After 3 years

= 46200 + 6930

= 53130 Rs

⇨Therefore total profit will be

= 53130 - 40000

= 13130 Rs

Tags: Math-Class-8