Given sec θ =13/12 calculate all other trigonometric ratios.

Solution:

⇨Given,

$Given sec θ =13/12 calculate all other trigonometric ratios.$

⇨We Know That,

$\large sec\Theta=\frac{13}{12}=\frac{h}{b}$

⇨Therefore, h=13, b=12, p=?

⇨From Pythagoras Theorem

$Given sec θ =13/12 calculate all other trigonometric ratios.$

$\large \Rightarrow p^2=169-144$

$\large \Rightarrow p^2=25$

$\large \Rightarrow p^2=5^2$

$\large \Rightarrow p=5$

⇨Now,

$\large sin\Theta =\frac{p}{h}=\frac{5}{13}$

$\large cos\Theta =\frac{b}{h}=\frac{12}{13}$

$\large tan\Theta =\frac{p}{b}=\frac{5}{12}$

$\large cot\Theta =\frac{b}{p}=\frac{12}{5}$

$\large cosec\Theta =\frac{h}{p}=\frac{13}{5}$