If cot θ = 7/8, evaluate (i) \large \frac{(1+sin\theta)(1-sin\theta)}{(1+cos\theta)(1-cos\theta)} (ii) \large cot^2\theta ?

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 Solution:
⇨ Given
⇨ cot θ = 7/8 = b/p
⇨ Therefore b = 7, p = 8, h = ?
From Pythagoras Theorem
     If cot θ = 7/8,  evaluate (i) \large \frac{(1+sin\theta)(1-sin\theta)}{(1+cos\theta)(1-cos\theta)} (ii) \large cot^2\theta ?

(i)  

(ii) 

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