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Solution:
(b+c)(c+a)(a+b)+abc
= (b+c){c(a+b)+a(a+b)}+abc
= (b+c)(ac+bc+
+ab)+abc
= (b+c)(+ab+ac+bc)+abc
= (b+c){+a(b+c)+bc}+abc
= (b+c)+a(b+c)(b+c)+bc(b+c)+abc
= a(b+c){a+b+c}+bc{b+c+a}
= (a+b+c){a(b+c)+bc}
= (a+b+c)(ab+ac+bc)
Tags:
Advance Math Class 8